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    How do you use recursion in linear search?What is linear recursion in Python?How do you code a linear search in Python?What is linear and binary search in Python?

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Given an unsorted array and an element x, search x in the given array. Write recursive C code for this. If the element is not present, return -1. 

Approach : The idea is to compare x with the last element in arr[]. If the element is found the last position, return it. Else recur searchElement() for remaining array and element x. 

C++

#include

using namespace std;

int searchElement(int arr[], int size, int x)

    size--;

    if (size < 0)

        return -1;

    

    if (arr[size] == x)

        return size;

    

    return searchElement(arr, size, x);

int main()

    int arr[] = 17, 15, 11, 8, 13, 19;

    int size = sizeof(arr) / sizeof(arr[0]);

    int x = 11;

    int idx = searchElement(arr, size, x);

    if (idx != -1) 

        cout << "Element " << x << " is present index " <

    else 

        cout << "Element " << x << " is not present in the array";

    return 0;

C

#include

int elmntSrch(int arr[], int size, int x)

    int rec;

    size--;

    if (size >= 0)

        if (arr[size] == x)

            return size;

        else

            rec = elmntSrch(arr, size, x);

    

    else

        return -1;

    return rec;

int main(void)

    int arr[] = 12, 34, 54, 2, 3;

    int size = sizeof(arr) / sizeof(arr[0]);

    int x = 3;

    int indx;

    indx = elmntSrch(arr, size, x);

    if (indx != -1)

        printf("Element %d is present index %d", x, indx);

    else

        printf("Element %d is not present", x);

    return 0;

Java

class Test

     static int arr[] = 12, 34, 54, 2, 3;

     static int recSearch(int arr[], int l, int r, int x)

     

          if (r < l)

             return -1;

          if (arr[l] == x)

             return l;

          if (arr[r] == x)

             return r;

          return recSearch(arr, l+1, r-1, x);

     

     public static void main(String[] args) 

     

        int x = 3; 

        int index = recSearch(arr, 0, arr.length-1, x);

        if (index != -1)

           System.out.println("Element " + x + " is present index " + 

                                                    index);

        else

            System.out.println("Element " + x + " is not present");

        

 

Python3

def recSearch( arr, l, r, x):

    if r < l:

        return -1

    if arr[l] == x:

        return l

    if arr[r] == x:

        return r

    return recSearch(arr, l+1, r-1, x)

arr = [12, 34, 54, 2, 3]

n = len(arr)

x = 3

index = recSearch(arr, 0, n-1, x)

if index != -1:

    print ("Element", x,"is present index %d" %(index))

else:

    print ("Element %d is not present" %(x))

C#

using System;

static class Test

    static int []arr = 12, 34, 54, 2, 3;

    static int recSearch(int []arr, int l, int r, int x)

    

        if (r < l)

            return -1;

        if (arr[l] == x)

            return l;

        if (arr[r] == x)

            return r;

        return recSearch(arr, l+1, r-1, x);

    

    public static void Main(String[] args) 

    

        int x = 3; 

        int index = recSearch(arr, 0, arr.Length-1, x);

        if (index != -1)

        Console.Write("Element " + x + 

                      " is present index " + index);

        else

            Console.Write("Element " + x + 

                          " is not present");

        

PHP

function recSearch($arr, int $l, 

                   int $r, int $x)

    if ($r < $l)

        return -1;

    if ($arr[$l] == $x)

        return $l;

    if ($arr[$r] == $x)

        return $r;

     return recSearch($arr, $l+1, $r-1, $x);

    $arr = array(12, 34, 54, 2, 3); $i;

    $n = count($arr);

    $x = 3;

    $index = recSearch($arr, 0, $n - 1, $x);

    if ($index != -1)

    echo "Element"," ", $x," ", 

         "is present index ", $index;

    else

        echo "Element is not present", $x;

?>

Javascript

Output

Element 11 is present index 2

Explanation

We iterate through the array from the end by decrementing the size variable and recursively calling the function searchElement(). If the size variable becomes less than zero it means the element is not present in the array and we return -1. If a match is found, we return the size variable which is the index of the found element. This process is repeated until a value is returned to main().

It is important to note that if there are duplicate elements in the array, the index of the last matched element will be returned since we are (recursively) iterating the array from the end.

Time Complexity: O(N), where N is the size of the given array.
Auxiliary Space: O(1)

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
 


The program output is also shown below.. /* C Program to implement Linear Search Algorithm recursively */. #include . int RecursiveLS(int arr[], int value, int index, int n). int pos = 0;. if(index >= n). return 0;.

What is linear recursion in Python?

A linear recursive function is a function that only makes a single call to itself each time the function runs (as opposed to one that would call itself multiple times during its execution). The factorial function is a good example of linear recursion.

How do you code a linear search in Python?

Python Program. def linear_Search(list1, n, key):. # Searching list1 sequentially.. for i in range(0, n):. if (list1[i] == key):. return i.. return -1.. list1 = [1 ,3, 5, 4, 7, 9]. key = 7..

What is linear and binary search in Python?

Linear search is a search that finds an element in the list by searching the element sequentially until the element is found in the list. On the other hand, a binary search is a search that finds the middle element in the list recursively until the middle element is matched with a searched element. Tải thêm tài liệu liên quan đến nội dung bài viết Linear search using recursion in python programming python

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